(a) an optically inactive mixture a (c6h10o4) can be resolved into enantiomers and has the following nmr spectra: 13c nmr: δ 13.5, δ 41.2, δ 177.9 1h nmr: δ 1.13 (6h, d, j = 7 hz); δ 2.65 (2h, quartet, j = 7 hz); δ 9.9 (2h, broad s, disappears after d2o shake) draw either enantiomer; use wedge/dash bonds, including for any h on a chirality center.

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%

it would be b. 6co2 + 6h2o --> c6h12o6 + 6o2