The work function of indium is 6.56 x 10^-19 j. what is the minimum frequency of a photon that will eject an electron from the indium metal surface?
1. 9.90 x 10^14 hz
2. 2.97 x 10^23 hz
3. 3.42 x 10^14 hz
4. 4.57 x 10^26 hz
5. 2.19 x 10^-27 hz

1. 9.90 x 10^14 Hz

Explanation:

The work function is the minimum energy required to eject electron's from the surface of the metal. The frequency of photons that are capable of doing this is called the threshold frequency. Given the work function, the threshold frequency can be calculated in the following way

Work function = Planck's constant * frequency

6.56 x 10^-19 J = 6.62607004 × 10-34 m²-kg/s  * f

                      f = 9.90 x 10^14 Hz

10 years is the answer