Consider the reaction
s2cl2(l) + ccl4(> cs2(g) + 3cl2(g); dh° = 84.3 kj
if the above reactants and products are contained in a closed vessel and the reaction system is at
equilibrium, the number of moles of cs2 can be increased by
a) increasing the size of the reaction vessel.
b) adding some cl2 to the system.
c) adding some s2cl2 to the system.
d) decreasing the temperature of the reaction system.
e) adding some ccl4 to the system.

A), C), and E)

Explanation:

We need to use the Le Chatelier´s principle to answer this question as follows:

A)  Increasing the size of the reaction vessel has the effect of decreasing pressure, so the equilibrium will shif to the side that has greater pressure which in this case is the products, so we the number of moles of CS2 will increase.

B) If we add more product Cl2 to the system it will shift to the reactants  to counteract the change in the equilibrium; therefore, some CS2 will be consumed.

C) If we add reactant S2Cl2 to the system it will shift to the product side therby increasing the number of moles of CS2

D) The reaction is endothermic so it will shift to the reactant side.

E) Adding more reactant CCl4  will shift the equilibrium to the right side favoring more CS2

nacl or sodium chloride is an ionic compound. this is because an ionic compound pertains to a compound that consists of positively and negatively charged ions. in this case, na (sodium) has a tendency to lose one electron when it reacts with with other atoms, so the resulting sodium ion contains 11 protons and 10 electrons, thus making it positively charged (na+), when chlorine reacts, it usually gains one electron to form an ion called chloride, thus making it negatively charged ( since the ions are oppositely charged, they attract.