Consider a galvanic cell based on the reaction al^3+_(aq) + mg_(s) rightarrow al_(s) + mg^2+ _(aq) the half-reactions are al^3+ + 3 e^- rightarrow al e degree = - 1.66 v mg^2+ + 2 e^- rightarrow mg e degree = - 2.37 v give the balanced cell reaction and calculate e degree for the cell.

The standard cell potential of the cell is -0.71 V

Explanation:

The half reactions follows:

Oxidation half reaction:    ( × 3)

Reduction half reaction:    ( × 2)

The balanced cell reaction follows:

To calculate the of the reaction, we use the equation:

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

Putting values in above equation, we get:

Hence, the standard cell potential of the cell is -0.71 V

why do the isotopes of a particular element behave differently in nuclear reactions but the same in chemical reactions? chemical reactions involve changes to electrons in an atom; isotopes do not differ in electrons, and so they react the same way during chemical changes.