For the following forward chemical equation identify the acid / base / conjugate acid and conjugate base.
hco3-+h2o. oh-+h2co3

d: the voltage of the secondary coil is less than that of the primary coil.

im not suree sorry if wrong

sure im new too!

explanation:

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.