The action of some commercial drain cleaners is based on the following reaction: 2 naoh(s) + 2 al(s) + 6 h2o(l) → 2 naal(oh)4(s) + 3 h2(g) what is the volume of h2 gas formed at stp when 6.32 g of al reacts with excess naoh?

Answer : The volume of gas formed at STP is 7.86 liters.

Explanation :

The balanced chemical reaction will be:

First we have to calculate the moles of .

Molar mass of Al = 27 g/mole

Now we have to calculate the moles of gas.

From the reaction we conclude that,

As, 2 mole of react to give 3 mole of

So, 0.234 moles of react to give moles of

Now we have to calculate the volume of gas formed at STP.

As, 1 mole of gas contains 22.4 L volume of  gas

So, 0.351 mole of gas contains volume of gas

Therefore, the volume of gas formed at STP is 7.86 liters.

its mg hope this