Each molecule of hemoglobin combines with four molecule of oxygen in order to transport oxygen throughout the body. it is observed that 1.51 g of hemoglobin combines with 2.30 ml of o 2 at 37 °c and 743 torr. what is the molar mass of hemoglobin?

68325.8 g/mol

Explanation:

Given that:

Pressure = 743 torr

Temperature = 37 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (37 + 273.15) K = 310.15 K  

T = 310.15 K  

Volume = 2.30 mL = 0.00230 L ( 1 mL = 0.001 L)

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 62.364 L.torr/K.mol

Applying the equation as:

743 torr × 0.00230 L = n × 62.364 L.torr/K.mol  × 310.15 K  

⇒n = 8.84 × 10⁻⁵ moles

Since, given that:-

4 moles of oxygen gas is transferred by 1 mole of haemoglobin.

8.84 × 10⁻⁵ moles  of oxygen gas is transferred by 8.84 × 10⁻⁵/4 moles of haemoglobin.

Moles of haemoglobin = 2.21 × 10⁻⁵ moles

Mass = 1.51 g

The formula for the calculation of moles is shown below:

Thus,

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