What is the limiting reagent when 3.1 mol of so2 react with 2.7 mol of o2
according to the equation: 2so2(g)+o2(g) --> 2so3(g)

The number of moles of SO₃ produced by  SO₂  are less so it is limiting reactant.

Explanation:

Given data:

Number of moles of SO₂ = 3.1 mol

Number of moles of O₂ = 2.7 mol

Limiting reactant = ?

Solution:

Chemical equation;

2SO₂ + O₂ → 2SO₃

Now we will compare the moles of SO₃ with O₂  and  SO₂.

                      SO₂         :       SO₃

                         2           :        2

                        3.1          :       3.1

                       O₂           :        SO₃

                          1            :          2

                         2.7          :         2×2.7 = 5.4 mol

The number of moles of SO₃ produced by  SO₂  are less so it is limiting reactant.

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