Compounds x and y are both c7h15cl products formed in the radical chlorination of 2,4-dimethylpentane. base-promoted e2 elimination of x and y gives, in each case, a single c7h14 alkene. both x and y undergo an sn2 reaction with sodium iodide in acetone solution to give c7h15i products; in this reaction y reacts faster than x. what is the structure of x?

X  is 3-chloro-2,4-dimethylpentane

Explanation:

The radical chlorination of 2,4-dimethylpentane may give three products.

Based on the information that

i) both the products gives single alkene on elimination and

ii) both the products also undergoes SN2 reaction but Y reacts faster than X

We may conclude that as SN2 reaction is faster in primary alkyl halides as compared to secondary or tertiary so Y must be primary or secondary and it cannot be tertiary alkyl halide.

The possible products are shown in the figure.

The structure of X is shown in the figure.

c8h10 is your answerr

b. accuracy of the data matters alot more than its number of digits, organization or amount of detail. quantitative observation is more accepted than the qualitative observation.