At 300 k and 20 atm, the compression factor of a gas is 0.86. calculate (a) the volume occupied by 8.2 mmol of the gas under these conditions and (b) an approximate value of the second virial coefficient b at 300 k. (20 pts)

Answer :

(a) The volume occupied by 8.2 mmol of the gas under these conditions is, 0.0087 L.

(b) The value of the second virial coefficient 'b' at 300 K is -0.16

Explanation :

Part (a) :

The formula for compression factor of a gas (Z) is:

where,

Z = impressibility factor = 0.86

P = pressure of gas = 20 atm

= volume of gas = ?

T = temperature of gas = 300 K

n = number of moles of gas = 8.2 mmol = 0.0082 mol    (1 mmol = 0.001 mol)

R = gas constant  = 0.0821 L.atm/mol.K

Now put all the given values in the ideal gas equation, we get:

Thus, the volume occupied by 8.2 mmol of the gas under these conditions is, 0.0087 L.

Part (b) :

First we have to calculate the volume for ideal gas.

Formula used :

Now we have to calculate the value of the second virial coefficient 'b' at 300 K.

Thus, the value of the second virial coefficient 'b' at 300 K is, -0.16

a:

by the combination of an unlimited number of elements

definition

                    entropy is a measure of the randomness or the extent of disorder of a chemical process.

                      enthalpy is a measure of the heat change of a reaction occurring at a constant pressure.

measurement units:

                        entropy is measured in joule per kelvin (jk⁻¹)   whereas enthalpy is measured in joule per mole (jmol⁻¹)

requirements:

                            entropy has no requirements or limits, and its change is measured by the division between the heat change of the chemical process and the temperature.

                              in contrast, enthalpy can only be related to the heat change of the reaction under standard conditions.