Molar mass is used in a conversion factor to calculate and uses the units of (not an multiple choice)

37.5 L

Explanation:

Data Given

volume of H₂S = 25.0 L

volume of O₂ = ?

Solution:

Reaction of Oxygen and H₂S is as below

                      2H₂S    +    3O₂   > 2SO₂ + 2H₂O

                      2 mole       3 mole

we come to know that 2 mole of H₂S  combine with 3 mole of O₂ and produce SO₂ and water

So,

Now we will calculate that how many liters of O₂ is Required to react with H₂S

So for this first we find moles of 25.0 L H₂S

  no. of moles = Volume in dm³ / molar volume at STP (22.4 dm³/mol)

So, we know

1 dm³ = 1 L

Put values in the above formula:

             no. of moles = 25 L / 22.4 L /mol

             no. of moles = 1.11 mol

So now apply Unity formula

if 2 mole of H₂S react with 3 mole of O₂ then how many mole will react with 1.11 mol of H₂S

                     2 mole of H₂S ≅ 3 mole of O₂

                     1.11 mole of H₂S ≅ ? mole of O₂

by doing cross multiplication

mole of O₂ = 3 mole x 1.11 mole / 2 mole

mole of O₂ = 1.67 mol

Now,

Convert mole to volume by using below formula

         no. of moles = Volume in dm³ / 22.4 dm³/mol

Rearrange the above equation

         Volume in dm³ =  no. of moles x 22.4 dm³/mol

Put values in above equation

        Volume in dm³ = 1.67 mol x 22.4 dm³/mol

        Volume in dm³ =  37.5 dm³ or L

So 37.5 L of volume is required to react with 25 L of H₂S

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metals are good conductor of electricity. it has free electrons on their surface. according to electron pool theory, each atom present in a metal crystal losses all of its valence electron and as a result a pool of free is form. these pool of electrons are free to move and   conduct electricity easily   while making metal as good conductor.

the correct answer is a. the ability of electrons to flow throughout the metal.

if it's not useful, feel free to report for mistake in answer.