Ahot air balloon filled with 1.27x10^6l of an ideal gas on a cool morning of 11 degrees c. the air is heated to 105 degrees c. what is the volume of the air in the ballon after it is heated? assume that none of the gas escapes from the balloon. l=

New volume = L

Explanation:

Using Charle's law  

Given ,  

V₁ = L

V₂ = ?

T₁ = 11 °C

T₂ = 105 °C  

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (11 + 273.15) K = 284.15 K  

T₂ = (105 + 273.15) K = 378.15 K  

Using above equation as:

New volume = L

la respuesta es si te gusta hacer lo que siempre haces cuando nunca ves a alguien en el espejo porque sabes que no siempre están ahí.

answer: -

reaction:

na + cl ⇌ nacl

balanced chemical equation:

na + 2cl ⇌ nacl2

sodium + clorine goes to form sodium chloride (table salt).

the product is nacl2.

and the reactants are na and cl.

(note: if you don’t know what ⇌ means, read below: -

⇌(double head arrow) means reversible reaction).