Chemistry, 06.12.2019 04:31 bikkiecuanas13

Using what you have learned about the three forms of writing chemical equations, classify each of the presented equations as either a molecular equation, a complete ionic equation, or a net ionic equation. drag the appropriate equations to their respective bins.
a)ca2+(aq)+so42−(aq)→caso4(s)b)cuso 4(aq)+2koh(aq)→cu(oh)2(s)+k2so4(aq) c)ba2+(aq)+so42−(aq)→baso4(s)
d)ag+(aq)+no3−(aq)+i−(aq)→agi(s)+no 3−(aq)e)cu2+(aq)+so42−(aq)+2k+(aq)+ 2oh−(aq)→cu(oh)2(s)+2k+(aq)+so42−(a q)f)(bano3)2(aq)+k2so4(aq)→baso4(s) +2kno3(aq)molecular equationcomplete ionic equation

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Answer from: andreanelson5788

Explanation:

Net ionic equation is a chemical equation in which no spectator ions are written.

Complete ionic equation is a chemical equation in which spectator ions are written.

Molecular equation is a chemical equation in which molecuklar formula of compounds are but no ions .

a) $Ca^{2+}(aq)+SO_4^{2-}(aq)\rightarrow CaSO_4(s)$

The given equation is net ionic equation as there are calcium ions and sulfate ions present in the chemical equation.

b) $CuSO_4(aq)+2KOH(aq)\rightarrow Cu(OH)_2(s)+K_2SO_4(aq)$

The given equation is a molecular equation as there are no ions present but only compounds on both reactant and product sides.

c) $Ba^{2+}(aq)+SO_4^{2-}(aq)\rightarrow BaSO_4(s)$

The given equation is net ionic equation as there are barium ions and sulfate ions present in the chemical equation.

d) $Ag^+(aq)+NO_3^{-}(aq)+I^-(aq)\rightarrow AgI(s)+NO_3^{-}(aq)$

The given equation is complete ionic equation as there are silver ions, nitrate ions, and iodide ions present in the chemical equation.

e) $Cu^{2+}(aq)+SO_4^{2-}(aq)+2K^+(aq)+2OH^-(aq)\rightarrow Cu(OH)_2(s)+2K^+(aq)+SO_4^{2-}(aq)$

The given equation is complete ionic equation as there are copper ions,sulfate ions, potassium ions and hydroxide ions present in the chemical equation.

f) $Ba(NO_3)_2(aq)+K_2SO_4(aq)\rightarrow BaSO_4(s)+2KNO_3(aq)$

The given equation is a molecular equation as there are no ions present but only compounds on both reactant and product sides.

Answer from: Quest

D. is the answer hope that you

Answer from: Quest

it can be observed without changing the identity of the object.

it depends on what substance you're talking about as well as many other factors. in quantum mechanics, the observation of particles affects the observers ability to measure certain properties. for example: you can know the velocity of a particle, but you can't know it's position; or you can know it's position, but not it's velocity. it's like trying to find out where a grain of sand is by throwing other grains of sand at it. once you find out where it is, it's been moved. it's also like trying to find an answer to the question of whether or not a tree falling in a forest makes a sound if nobody is there to hear it. paradoxically, the only way to find out is to be there and hear it.

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