How many ounces of a 1212% alcohol solution must be mixed with 33 ounces of a 2020% alcohol solution to make a 1414% alcohol solution? the number of ounces of the 1212% alcohol solution that needs to be mixed is nothing ounces. (simplify your answer.)

99 ounces of the 12% alcohol solution that needs to be mixed.

Explanation:

Let the volume of 12% alcohol solution be x.

Volume of alcohol added = 0.12 x

Volume of 20% alcohol solution  = 33 ounces

Volume of alcohol in 20% of alcohol solution =

Total volume of alcohol after addition = (0.12 x +6.6) Oz

Total volume of alcohol solution after addition = x + 33 Oz

Percentage of alcohol solution after addition = 14%

Also ,Total volume of alcohol after addition =

Solving for x :

x = 99 ounces

99 ounces of the 12% alcohol solution that needs to be mixed.

in chemistry, a solution’s concentration is how much of a dissolvable substance, known as a solute, is mixed with another substance, called the solvent. the standard formula is c = m/v, where c is the concentration, m is the mass of the solute dissolved, and v is the total volume

ill try to . no promises tho.

explanation: