The molar heats of fusion and vaporization of argon are 1.3 kj/mol and 6.3 kj/mol respectively, and argon's melting point and boiling point are -190°c and -186 °c, respectively. calculate the entropy changes for the fusion and vaporization of argon.

The entropy changes for the fusion and vaporization of argon is 15.634 J/mol K and 72.289 J/mol K respectively.

Explanation:

The molar heats of fusion =

Melting point of argon = -190°C = 83.15 K

Entropy changes for the fusion =

The molar heats of vaporization of argon =

Boiling point of argon = -186°C = 87.15 K

Entropy changes for the vaporization=

answer: i have one answer

acids are substances that ionize (break off) in an aqueous solution to produce hydrogen (h+) ions

explanation:

hope this and sorry i could only come up with one answer!