The reaction of ch3 ch2 no2 + oh- --> h2 o + ch3 chno2 - is a second order and k at 273 k is 39.1 min-1mol-1 an aqueous solution is 0.005 molar in nitroethane and 0.006 molar in naoh. how long will it take for 90% of the nitroethane to react?

t = 23,4 min

Explanation:

The integrated rate law for a reaction of the form A + B → Products is:

(1)

For the reaction:

CH₃CH₂NO₂ + OH⁻ → H₂O + CH₃CHNO₂

The [A]₀ is [CH₃CH₂NO₂]₀ = 0,005M and [B]₀ = [OH⁻]₀ = 0,006M

90% of [A]₀ is 0,005M×0,9 = 0,0045M consumed

That means [A] = 0,005M - 0,0045M = 0,0005M

And [B] = 0,006M - 0,0045M = 0,0015M

Replacing in (1) knowing k = 39,1min⁻¹mol⁻¹:

ln 2,5 = (39,1min⁻¹mol⁻¹× 0,001M) t

t = 23,4 min

I hope it helps!

the density(ratio between mass and volume as m/v) decreases from top to bottom in periodic table group as the size increases and nuclear charge decreases. but in periods density increases from left to right as atom size decreases and nuclear charge increases.