If the rate of decrease for the partial pressure of n2h4 in a closed reaction vessel is 80 torr/h , what is the rate of change for the partial pressure of nh3 in the same vessel?

Pressure of NH3 increases at the rate of 160torr/hr

Explanation:

According to the equation below

N2H4 (g) + H2 (g) ==> 2 NH3 (g)

It shows that 1mol of N2H4 will gives 2mol of NH3

Therefore, if the partial pressure rate of N2H4 is 80torr/hr, the partial pressure of NH3 increases by 2×80=160torr/hr

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)