Astudent must use 220 ml of hot water in a lab procedure. calculate the amount of heat required to raise the temperature of 220 ml of water from 30.0 /c to 100.0 /c. c for water is 4.184 j/g cc

64,433.6 Joules

Explanation:

We are given;

We are required to calculate the amount of heat required to raise the temperature.

Q = mcΔT , where m is the mass, c is the specific heat, ΔT is the change in temperature.

Density of water is 1 g/mL

Thus, mass of water is 220 g

ΔT = 100°C - 30°C

    = 70°C

Therefore;

Amount of heat, Q = 220g × 4.184 J/g°C × 70°C

                               = 64,433.6 Joules

Thus, the amount of heat required to raise the temperature of water is 64,433.6 Joules

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