Calculate the mass of oxygen produced from the decomposition of 75.0 g of potassium chlorate?

We are given the amount of potassium chlorate. This will be our starting point.

75.0 g KClO3 (1 mol KClO3 /122.55 g KClO3) (3 mol O2/2 mol KClO3) ( 32 g O2 / 1mol O2) = 58.75 g O2

Thus, the answer is 28.88g H2O.

29.4 g

Explanation:

Let's consider the decomposition of potassium chlorate.

KClO₃ → KCl + 1.5 O₂

The molar mass of KClO₃ is 122.55 g/mol. The moles of KClO₃ in 75.0 g are:

75.0 g × (1 mol/ 122.55 g) = 0.612 mol

The molar ratio of KClO₃ to O₂ is 1:1.5. The moles of O₂ are 1.5 × 0.612 mol = 0.918 mol

The molar mass of O₂ is 32.00 g/mol. The mass of O₂ corresponding to 0.918 moles is:

0.918 mol × (32.00 g/mol) = 29.4 g

beta decay is the answer

the earth would become to overheated and everything alive on it will eventually die from overheating. plants will eventually die as well, water will evaporate, and it will be nothing but a hot planet without anything living on it.