A1 mol sample of gas has a temperature of 225k, a volume of 3.3l, and a pressure of 500 torr. what would the temperature be if the amount of gas remains constant while pressure dropped to 210 torr, and the volume dropped to 2.75l?

78.75 K

We are given;

We are required to calculate the new temperature, T₂

P₁V₁/T₁ = P₂V₂/T₂

We can calculate the new temperature, T₂;

Rearranging the formula;

T₂ =(P₂V₂T₁) ÷ (P₁V₁)

  = (210 torr × 2.75 L × 225 K) ÷ (500 torr × 3.3 L)

  = 78.75 K

Therefore, the new volume of the sample is 78.75 K

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j