Write the overall cell reaction for the galvanic cell given below. pt(s) h2(g) h+(aq) cl2(g) cl-(aq) pt(s) a) pt(s) + h2(g) + cl-(aq) → pt(s) + 2 h+(aq) + 2 cl2(g) b) 2 h+(aq) + 2 cl2(g) → 2 hcl(aq) c) h2(g) + cl2(g) → 2 h+(aq) + 2 cl-(aq) d) no reaction would occur because there is no salt bridge. c

True is ur answer : )

1.75 is the weight of one medium egg

A. ​it generates energy from carbohydrates.b. it requires activation by oxygen.​c. ​it is used by cells to dispose of excess electrons

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.