Nylon 6,6 may be formed by means of a condensation polymerization reaction in which hexamethylene diamine [nh2-(ch2)6-nh2] and adipic acid react with one another with the formation of water as a byproduct. what masses of (a) hexamethylene diamine and (b) adipic acid are necessary to yield 26 kg of completely linear nylon 6,6? this polymerization reaction occurs according to the following equation:

(a)13.351 kg of hexamethylene diamine are necessary to yield 26 kg of completely linear nylon 6,6.

(b) 16.790 kg of dipic acid are necessary to yield 26 kg of completely linear nylon 6,6.

Explanation:

Nylon 6,6 compound can be formed by the hexamethylene diamine and adipic acid.

Molecular formula of adipic acid =

Molar mass of adipic acid = 146.14 g/mol

Molecular formula of hexamethylene amine =

Molar mass of hexamethylene damine =116.21 g/mol

Molecular formula of Nylon =

Molar mass of adipic acid = 226.32 g/mol

Number of moles of 20 kg Nylon:

To produce Nylon -6,6 requires one mole of adipic acid, one mole of hexamethylenediamine and two moles water.

The weight of adipic acid that required to produce 26 Kg of Nylon 6,6:

Therefore, 16.790 kg of dipic acid are necessary to yield 26 kg of completely linear nylon 6,6.

The weight of Hexamethylene diamine that required to produce 26 Kg of Nylon 6,6:

Therefore, 13.351 kg of hexamethylene diamine are necessary to yield 26 kg of completely linear nylon 6,6.

where's the diagram?

the increase of protons   hope this