Asound wave has a wavelength of 0.450
meters. if its speed in cold air is 330
meters/second, what is the wave's frequency?
select the correct answer
0.890 hertz
100 hertz
230 hertz
733 hertz

The wave's frequency is 733 hertz.

Explanation:

The wavelength (λ) is the minimum distance between two points of the wave that are in the same state of vibration.

Frequency (f) is the number of vibrations that occur in a unit of time.

The speed of propagation (v) is the speed with which the wave propagates in the middle. Relate wavelength (λ) and frequency (f) inversely proportionally using the following equation: v = f * λ.

In this case you know that:

Replacing you get:

Then:

f=733.33 hertz≅733 hertz

Finally,  the wave's frequency is 733 hertz.

answer: the figure is attached herewith.

step-by-step explanation:   we are given to sketch a unit circle and label the terminal points corresponding to

in the attached figure, we have drawn a unit circle, with centre at o(0,0) and radius 1 unit. we have labelled the points a, b, c, d and e corresponding to the angles below

∠aox = 60°,

∠box = 120°,

∠cox = 180°,

∠dox = 240°,

∠eox = 300°.

and the coordinates are a(0.5,1), b(-0.5,1), c(-1,0), d(-0.5,-1) and e(0.5,-1).

thus, the answer is complete.

you need to have a picture of the atom that way we can answer it