How many grams of c6h6o3 will react with 97.0grams of o2?

c6h6o3+3o2 ===> 6co+3h2o

127.3 g

Explanation:

Data Given

mass of O₂= 97 g

mass of C₆H₆O₃ = ?

Reaction Given:

                C₆H₆O₃ + 3O₂ >  6CO + 3H₂O

Solution:

First find the mass of C₆H₆O₃ from the reaction that it combine with how many grams of oxygen (O₂).

Look at the balanced reaction

                  C₆H₆O₃  +   3O₂       >  6CO + 3H₂O

                    1 mol        3 mol

So 1 mole of C₆H₆O₃ combine with 3 moles of O₂  

Now

convert the moles into mass for which we have to know molar mass of C₆H₆O₃ and O₂

Molar mass of C₆H₆O₃

Molar mass of C₆H₆O₃ = 6(12) + 6(1) +3(16) = 72 + 6 + 48

Molar mass of C₆H₆O₃ = 126 g/mol

mass of C₆H₆O₃

                 mass in grams = no. of moles x molar mass

                 mass of C₆H₆O₃ = 1 mol x 126 g/mol

                 mass of C₆H₆O₃ = 126 g

Molar mass of O₂ = 2(16)

Molar mass of O₂= 32 g/mol

mass of O₂

                mass in grams = no. of moles x molar mass

                mass of O₂ = 3 mol x 32 g/mol

                 mass of O₂ = 96 g

So,

96 g of O₂ combine with 126 g of C₆H₆O₃ then how many grams of C₆H₆O₃ will combine with 97.0grams of O2

Apply unity Formula

                      96 g of O₂ ≅ 126 g of C₆H₆O₃

                      97 g of O₂ ≅  X g of C₆H₆O₃

By cross multiplication

                    X g of O₂ = 126 g x 97 g / 96 g

                   X g  of O₂ = 127.3 g

127.3 g of C₆H₆O₃ will combine with 97 g of O₂

So

mass of C₆H₆O =  127.3 g

a 20-cm-long, cylindrical graphite (pure carbon) rod is inserted into an oxidizing atmosphere at 1145 k and 1.013 x 105 pa pressure. the oxidizing process is limited by the diffu- sion of oxygen counterflow to the carbon monoxide that is formed on the cylindrical surface.