What is the molarity of a solution in which 58.5 grams of nacl are dissolved in 1.0 l of solution?

Molarity = 1 M

Explanation:

Data given

mass of Nacl = 58.5 g

Volume of solution = 1 L

Solution:

To find the Molarity we have following formula

      Molarity = no. of moles of solute / 1 L of solution. . . . . . . . . (1)

Now

First we have to find number of moles of NaCl

Formula Used

                     No. of moles = Mass in g /molar mass . . . . . . . . . . . (2)

Molar mass of NaCl = 23 + 35.5

Molar mass of NaCl = 58.5 g/mol

Put values in equation 2

                      No. of moles = 58.5 g / 58.5 g/mol

                      No. of moles = 1 mol

Now,

Put values in equation 1

               Molarity = 1 mol  / 1 L of solution

               Molarity = 1 M

So,

The molarity of 58.5 grams of NaCl in 1.0 L of solution is 1.

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer