If you combine 300.0 ml of water at 25.00 ∘ c and 120.0 ml of water at 95.00 ∘ c, what is the final temperature of the mixture? use 1.00 g/ml as the density of water.

Answer : The final temperature of the mixture is

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

And as we know that,

Mass = Density × Volume

Thus, the formula becomes,

where,

c = specific heat of water =

= density of water = 1.00 g/mL

= volume of water at = 300.0 mL

= volume of water at = 120.0 mL

= final temperature of mixture = ?

= initial temperature of water =

= initial temperature of water =

Now put all the given values in the above formula, we get

Therefore, the final temperature of the mixture is

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6