In the balanced equation, 4ko₂+2co₂→2k₂co₃+30₂ which two chemicals have a molar ratio of 4: 3

KO₂ and O₂  have 4:3 molar rato

Explanation:

Reaction Given

                  4KO₂+2CO₂→2K₂CO₃+3O₂

chemicals have a molar ratio of 4:3 = ?

Solution

First look at the Reaction

                     4KO₂ + 2CO₂→ 2K₂CO₃ + 3O₂

write the moles of the reactant and products that involve

                       4KO₂ + 2CO₂ →  2K₂CO₃ + 3O₂

                       4 mol    2 mol               2 mol      3 mol

So the coefficients shows the number of moles of that compound involve in the reaction,

if we look for each ratio of moles to other

So the  molar ratio of KO₂ to CO₂  is 4: 2

So the  molar ratio of KO₂ to K₂CO₃  is 4 : 2

So the  molar ratio of CO₂ to K₂CO₃  is 4 : 2

So the molar ratio of KO₂ to O₂  is 4: 3

It is clear that KO₂ and O₂ are the chemicals in this reaction that are in the 4:3 molar ratio

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