Grams of sodium chloride in 30ml of a 1.2m solution

Mass = 2.12 g

Explanation:

Given data:

Volume of sodium chloride solution = 30 mL (30/1000 = 0.03 L)

Molarity = 1.2 M

Grams of sodium chloride = ?

Solution:

Molarity = number of moles / volume in litter

Number of moles = Molarity × volume in litter

Number of moles =  1.2 M × 0.03 L

Number of moles =  0.036 mol

Mass in grams:

Mass = number of moles × molar mass of sodium chloride

Mass = 0.036 mol  × 58.5 g/mol

Mass = 2.12 g

it is a good conductor

explanation: