Chemistry, 10.12.2019 03:31 bheam12

Landslides are common around pittsburgh, pa. the area has lots of relief due to hilly igneous and metamorphic rocks. many landforms in the area contain a red layer of clay, colloquially termed the "red beds". what weathering process formed the red beds?

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Answer from: billycain9647

Oxidation (a type of chemical weathering)

Explanation:

Chemical weathering is defined as the process by which rocks are disintegrated into smaller particles by chemical reactions. There are different types of chemical weathering and the presence of materials i.e. acids, oxygen, water, and carbon dioxide in rocks can change the minerals found in different rocks. Oxidation is a type of chemical weathering which involves the reaction of oxygen with a substance. Oxidation is also the process that causes rusting of material. If a rock contains iron, it can also undergo oxidation (i.e. rust).

Answer from: Quest

Answerthis solution will not form a precipitateexplanationsolubility equilbrium: pbf₂(s) ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is $k_{sp} = [\text{pb}^{2+}][\text{f}^- ]^2 = 4 \times 10^{-8}$ (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as $q = [\text{pb}^{2+}]_{\text{initial}} \cdot [\text{f}^- ]^2_{\text{initial}}$ then, we can interpret q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product: $\begin{aligned} q & = [\text{pb}^{2+}]_{\text{initial}} \cdot [\text{f}^- ]^2_{\text{initial}} \\ & = (1.9 \times 10^{-3} ) (3.8\times 10^{3})^2 \\ & = 2.7 \times 10^{-8} \end{aligned}$ since q = 2.7 × 10⁻⁸ < ksp = 4 × 10⁻⁸, a precipitate will not form.

Answer from: Quest

im doing test rn im going with 2 but ill give answer if itss wrong, : )

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Landslides are common around pittsburgh, pa. the area has lots of relief due to hilly igneous and me...