If we mix 25 grams of sodium bromide with a large amount of potassium chloride, what will our theoretical yield of sodium chloride be?

the equation to solve it is nabr + kcl —> nacl + kbr

Theoretical yield of sodium chloride = 14.04 g

Explanation:

Given data:

Mass of sodium bromide = 25 g

Theoretical yield of sodium chloride = ?

Solution:

Chemical equation:

NaBr + KCl  → NaCl  + KBr

Number of moles sodium bromide:

Number of moles = Mass /molar mass

Number of moles = 25.0 g / 102.9 g/mol

Number of moles = 0.24 mol

Now we will compare the moles of NaCl with NaBr  .

                  NaBr         :               NaCl

                    1               :               1

                 0.24           :            0.24

Theoretical yield of sodium chloride:            

Mass  = moles × molar mass

Mass = 0.24 mol ×  58.5 g/mol

Mass =  14.04 g

what is the question here. i think you messed up.