Ammonia is produced by the following reaction. 3h2(g) + n2(g) > 2nh3(g) when 7.00 g of hydrogen react with 70.0 g of nitrogen, hydrogen is considered the limiting reactant because

To determine the limiting reactant, we first calculate the number of moles of the reactant.

7.00 g H2 ( 1 mol / 2.02 g ) = 3.47 mol H2
70.00 g N2 ( 1 mol / 28.02 g) = 2.50 mol N2

From the balanced reaction, we see that there is a 3 is to 1 ratio of the reactants. So, for every 3 moles of H2 we need 1 mole of N2. Given the amount of reactant, for 2.50 moles of N2 we need 7.5 moles of H2 which obviously we have a lesser amount. Hydrogen is the limiting reactant.

A. 17 hope this dudet

You use the atomic number to find out how many protons and neutrons there are in the atom. you use the atomic mass to find out how many protons and electrons there are in the atom.