3) in the reaction below, how many grams of carbon dioxide are produced when iron iii
oxide (fe, o3) reacts completely with exactly 84 grams of carbon monoxide (co)? show
your work
fe2o3 + 3c0> 2fe + 3co,
molar masses:
co = 289
co2 = 449

132.03 g

We are given;

Fe₂O₃ + 3CO → 2Fe + 3CO₂

We are required to calculate the mass of CO₂ that will produced.

Moles = Mass ÷ Molar mass

Molar mass of CO = 28.01 g/mol

Therefore;

Moles of CO = 84 g ÷ 28.01 g/mol

                     = 2.9989 moles

                    = 3.0 moles

Moles of CO₂ = 3.0 Moles

But; mass = Moles × molar mass

Thus, mass of CO₂ = 3.0 moles × 44.01 g/mol

                                = 132.03 g

Hence, the mass of CO₂ produced from the reaction is 132.03 g

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

24

answer is: nuclear fusion produces elements that are heavier than helium.

nuclei combine to form a heavier nucleus, releasing energy.  

for example, fusion of hydrogen atoms at the sun.  

this fusion nuclear reaction is in the inner core of the sun and hydrogen (atomic number 1) is conveted into helium (atomic number 2).  

the inner core is the central region of the sun and all solar energy is produced in the core by nuclear fusion.