Give the chemical formula that corresponds to each of the following compounds: (a) sodium tetrahydroxozincate(ii) (b) dichlorobis(ethylenediamine)cobalt( iii) nitrate (c) triaquabromoplatinum(ii) chloride (d) tetra-amminedinitroplatinum(iv) bromide

a. Na₂[Zn(OH)₄]

b. [Co(Cl)₂(en)₂]NO₃

c. [Pt(H₂O)₃Br]Cl

d. [Pt(NH₃)₃(NO₂)₂]Br₂

Explanation:

(a) Sodium tetrahydroxozincate(II)

Zincate(II) indicates the metal is Zn²⁺, tetrahydroxo are 4OH⁻, that is

[Zn(OH)₄]²⁻. As the molecule is a neutral salt of sodium:

Na₂[Zn(OH)₄]

(b) Dichlorobis(ethylenediamine)cobalt(III) nitrate

The metal is Co³⁺, bis(ethylenediamine) are (en)₂ and dichloro are 2 Cl⁻, that is:

[CoCl₂(en)]⁺

The counterion is NO₃⁻, that is:

[CoCl₂(en)₂]NO₃

(c) Triaquabromoplatinum(II) chloride

The metal is Pt²⁺, ligands are 3 H₂O and 1 Br⁻, that is:

[Pt(H₂O)₃Br]⁺

The counterion is Cl⁻:

[Pt(H₂O)₃Br]Cl

(d) Tetra-amminedinitroplatinum(IV) bromide

The metal is Pt⁴⁺, ligands are 2 NO₂⁻ anf 3 NH₃, that is:

[Pt(NH₃)₃(NO₂)₂]²⁺

As counterion is Br⁻ you need 2 Br⁻ for the neutral salt, that is:

[Pt(NH₃)₃(NO₂)₂]Br₂

I hope it helps!

the number of valence electrons for each molecule or ion is shown beneath the structure. remember hydrogen will not have more than two electrons. this hydrogen is part of a covalent bond (sharing two electrons). a double bond here would cause hydrogen to share four electrons with phosphorus.

2b2t

explanation:

2b2t