Which process would require the least amount of energy? which process would require the least amount of energy? the process for the first ionization energy the process for the second ionization energy the process for the third ionization energy

The process of the first ionization energy

Explanation:

The ionization energy is the energy required to remove one electron for one isolated atom at the gas phase. The first electron to be removed is the valence electron which is far away from the nuclei. Because of that, this electron suffers a less attraction force.

For the second ionization energy, the electron will be closer to the nuclei, so it is more attracted, then a large amount of energy is necessary to remove it. For the third, the amount of energy will be larger. So, the first ionization energy requires the least amount of energy.

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.