The three aqueous ionic solutions below have total volumes of 25.0 ml for a, 50.0 ml for b, and 100.0 ml for c (all at 25°c). if each sphere represents 0.010 mol of ions, calculate: 1. the total molarity of ions for each solution a. (enter a number for example 0, 0.2, 0.25, 1, 2, 2.4, etc) b. (enter a number for example 0, 0.2, 0.25, 1, 2, 2.4, etc) c. (enter a number for example 0, 0.2, 0.25, 1, 2, 2.4, etc) 2. the lowest molarity of solute (find the one that has the lowest molarity and enter the molarity here (so enter a number such as 0.2, 0.5, 1, 1.5, 2, etc):

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answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol