Hydrochloric acid and calcium carbonate react to form calcium chloride, carbon dioxide, and water. if you being with 1.25 l of 1.20 m calcium carbonate and a stoichiometric amount of hydrochloric acid, how many grams of carbon dioxide will be formed

44.01 grams of carbon dioxide will be formed

Explanation:

This is the balance equation:

2HCl (aq)  +  CaCO₃ (aq)  →  CaCl₂ (aq)  +  CO₂ (g)  + H₂O (l)

Firstly, let's find out the moles for the salt, in the reactants.

Molarity . volume = Moles

1.2 mol/L . 1.25L = 1.5 moles

The stoichiometric amount of hydrochloric acid is 2.

Ratio between reactants is 2:1

If I have 2 moles of HCl, I need 1 mol of carbonate. I have 1.5 moles, so the salt is in excess and the limiting is the HCl.

Ratio between HCl and CO₂ is 2:1

If I have 2 moles of HCl, I make 1 mol of CO₂

The grams formed are just, the molar mass.

44.01 g

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