Agas storage cylinder in an ordinary chemical laboratory measures 4.4 cm wide and 17.cm high. this is the label on it.
contents: n2 gas
pressure: 29.8 atm
if the cylinder is opened and the gas allowed to escape into a large empty plastic bag, what will be the final volume of nitrogen gas, including what's collected in the plastic bag and what's left over in the cylinder? write your answer in liters. round your answer to 2 significant digits.

The final volume of nitrogen gas will be 7.7 L

Explanation:

Step 1: Data given

A gas storage cylinder measures 4.4 cm wide and 17 cm high.

The initial pressure = 29.8 atm

Step 2: Calculate the initial volume Vi

Vi = πr²h

⇒ with r = the radius = 4.4 / 2 = 2.2 cm

⇒ with h = the height of the cylinder = 17 cm

Vi = 258.49 cm³

Step 3: Calculate the final volume

We assume an equal number of moles at constant temperature.

This means P*V = constant

Pi*Vi = Pf*Vf

⇒ with Pi = the initial pressure = 29.8 atm

⇒ with Vi = the initial volume = 258.49 cm³ = 258.49 mL

⇒ with Pf = the final pressure = 1.00 atm

 ⇒ with Vf= the final volume = TO BE DETERMINED

Vf = (Pi*Vi)/Pf

Vf = (0.25849 * 29.8)/ 1.00

Vf = 7.70 L

The final volume of nitrogen gas will be 7.7 L

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !

2b2t

explanation:

2b2t