Agas occupied 23.55 l at 118.2 celsius. at what temp would the gas occupied 43.8 l

The gas occupies 43.8 L at a temperature of 219.8 °C

Explanation:

Step 1: Data given

Volume of the gas = 23.55L

Temperature = 118.2 °C

New volume = 43.8 L

Step 2: Calculate changed temperature

(P1*V1)/T1 = (P2*V2)/T2

Let's assume the pressure stays constant, then we have:

V1/T1 = V2/T2

⇒ with V1 = the initial volume = 23.55L

⇒ with T1 = the initial temperature = 118.2 °C

⇒ with V2 = the changed volume = 43.8 L

⇒ with T2 = the changed temperature = TO BE DETERMINED

23.55L/118.2°C = 43.8 L / T2

T2 = 219.8 °C

The gas occupies 43.8 L at a temperature of 219.8 °C

b is the correct

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