What is the electron configuration of bromine in this oxidation state? express your answer in condensed form, in order of increasing orbital energy. include brackets around any superscripts with two digits. for example, [xe]6s24f145d10 would be entered as [xe]6s^24f^{14}5d^{10}.

[Ar]3d^{10}4s^{2}4p^{6}

Explanation:

Electronic Configuration of Bromine : [Ar]3d^{10}4s^{2}4p^{5}

At oxidation state -1, electronic Configuration of Bromine : [Ar]3d^{10}4s^{2}4p^{6}

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied