Calculate the ratio of [cu2+]/[cu+] in an aqueous solution at eh = + 0.80 volt.

The ratio of in an aqueous solution is

Explanation:

The substance having highest positive potential will always get reduced and will undergo reduction react.

Oxidation half reaction:  

Reduction half reaction:      ( × 2)

Net cell reaction:  

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

To calculate the of the reaction, we use the equation:

To calculate the EMF of the cell, we use the Nernst equation, which is:

Concentration of pure solids and liquids are taken as 1 in the ratio

where,

= electrode potential of the cell = +0.80 V

= standard electrode potential of the cell = -0.21 V

n = number of electrons exchanged = 2

= Ratio of the concentration

Putting values in above equation, we get:

Hence, the ratio of in an aqueous solution is

the answer is