What is the limiting reactant when 8.4 moles of lithium react with 4.6 moles of oxygen gas?

unbalanced equation: li + o2 → li2o

show, or explain, all of your work along with the final answer.

To determine the limiting reactant, we divide the number of moles to its corresponding stoichiometric coefficient. Balancing the equation above, we get 4 Li + O2 = 2Li2O. For lithium, the result is 2.1 and for oxygen, the result is 4.6. The limiting reactant has the smaller ratio. So, the limitin reactant is lithium.

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