If the coefficient 2 is placed in front of the product tetraiodine nonaoxide (i4o9), then, how many atoms of each element must be accounted for on the otherwise of the equation

Number of iodine atoms = 2 × 4 = 8

Number of oxygen atoms = 2 × 9 = 18

Explanation:

Coefficient 2 is placed in front of the product tetraiodine nonaoxide:

=

Number of iodine atom in a single molecule tetraiodine nonaoxide = 4

Number of oxygen  atoms in a single molecule tetraiodine nonaoxide = 9

Coefficient 2 is placed in front of the product tetraiodine nonaoxide:

=

Number of iodine atoms = 2 × 4 = 8

Number of oxygen atoms = 2 × 9 = 18

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