Be sure to answer all parts. cyclopropyl chloride has been prepared by the free-radical chlorination of cyclopropane. draw the products for each equation of the stepwise mechanism for this reaction. be sure to include lone pair(s) of electrons where necessary. part 1 out of 3 ca45304fix1 draw structure plussign

See explanation and picture

Explanation:

In the picture you have the mechanism and procedure of this reaction. Remember that this kind of reactions are given in 3 steps:

Step 1: Initiation

The reaction begins with the separation of the chlorine (Cl2) into two radicals (atoms with a single unpaired electron) by the addition of uv light.

Step 2: Propagation

The formation of the chlorine radicals, is immediately followed by the propogation steps--steps directly involved in the formation of the product. The first step is the abstraction of the hydrogen atom from the carbon, to form the radical CH2, with a lone ion, and H-Cl.

Step 3: termination

The termination involve the destruction of the free-radical intermediates, typically by two of them coming together.

See the picture for mechanism.

since the atomic number is the number of protons in the nucleus, as we move to the left on the periodic table, the electrostatic pull between the nucleus and the valence electron shell decreases. as we move down a group (vertical column), the valence shell energy level gets further and further from the nucleus.