Beryllium is the first element in group 2 of the periodic table. calcium is the third element in the same group. which statement is true of both of their ions?

   

both of their ions will have a charge of +1.

 

   

both of their ions will have a charge of +2.

 

   

the charge on a calcium ion will be greater than the charge on a beryllium ion.

 

   

both of their ions will have a charge of -2.

 

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- You have to understand the overall concept

Elements in group 2 have 2 electrons in their outer shell and would lose 2 electrons to form 2+ions.

If you think about it, it makes sense.

An element itself has no charge as the number of protons and electrons but if it loses 2 electrons, it will have 2 more protons than electrons.

In short, your answer is 'both of their ions will have a charge of +2'

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answer: mercury

explanation:

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied