If you have 5.8 moles of zinc how many grams do you have

We have 379.20grams of zinc present.

Explanation: The SI base unit for amount of substance is the mole. 1 moles is equal to one moles zinc, or 65.38 grams.

We can relate the number of moles of zinc to the molar mass of zinc.

Since 1 mole of zinc = 65.38g/mol

Number of moles of zinc = mass of zinc/ molar mass of zinc

From the question, number of moles of Zinc is given as 5.8moles We can calculate the mass of zinc present in 5.8 moles as

5.8moles = mass of zinc/ 65.38gmol-1

When you cross multiply, you have:

Mass of zinc= 5.8moles×65.38gmol-1

Mass of zinc= 379.204g

Therefore the mass of zinc present is 379.20 grams

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :