Which statement best describes the light that will cause emission of electrons from a given metal through the photoelectric effect?
light with any intensity below a certain frequency
light with any intensity above a certain frequency
light with any frequency below a certain intensity
light with any frequency above a certain intensity

The correct (b) light with any intensity above a certain frequency

The explanation:

when Energy of a photon : E = hf

- The photoelectric effect works like this:

- If you shine light of high enough energy on to a metal, electrons will be emitted from the metal. Light below a certain threshold frequency, no matter how intense, will not cause any electrons to be emitted. Light above the threshold frequency, even if it's not very intense, will always cause electrons to be emitted.

it would be a gas formation

nacl or sodium chloride is an ionic compound. this is because an ionic compound pertains to a compound that consists of positively and negatively charged ions. in this case, na (sodium) has a tendency to lose one electron when it reacts with with other atoms, so the resulting sodium ion contains 11 protons and 10 electrons, thus making it positively charged (na+), when chlorine reacts, it usually gains one electron to form an ion called chloride, thus making it negatively charged ( since the ions are oppositely charged, they attract.