Achemist exploring potential fuels for use in outer space is considering using vaporized aluminum chloride as a fuel. what is the coefficient of o2 (g) when the following chemical equation is balanced using the smallest whole number integer coefficients?

9

Explanation:

The reaction given is:

AlCl₃(g) + O₂(g) → Al₂O₃(s) + ClO(g)

To be balanced, all the elements must have the same quantity on both sides of the chemical equation. Let's start by Al, which has 2 in the right and 1 on the left. We must multiply AlCl₃ by 2:

2AlCl₃(g) + O₂(g) → Al₂O₃(s) + ClO(g)

Now, let's do the same thing to Cl, which has 6 in the left and 1 in the right, so we multiply ClO by 6:

2AlCl₃(g) + O₂(g) → Al₂O₃(s) + 6ClO(g)

And now for O, which has 2 in the left and 9 in the right, so we multiply O₂ by 9/2:

2AlCl₃(g) + (9/2)O₂(g) → Al₂O₃(s) + 6ClO(g)

Because the question wants whole numbers, let's multiply all the coefficients by 2:

4AlCl₃(g) + 9O₂(g) → 2Al₂O₃(s) + 12ClO(g)

So, the coefficient of O₂ is 9.

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