The density of a substance is 4.8g/ml. what is the volume of a sample that is 19.2g?

4 mL

Explanation:

Data Given:

Density (d) = 4.8 g/mL

Mass of the substance (m) = 19.2 g

Volume of the sample (V) = ?

Solution:

Formula will be used

             d = m/V

As we have to find volume so rearrange the above equation

            V = m/d . . . . . . . . . . . (1)

Put values in above equation 1

          V = 19.2 g / 4.8 g/mL

          V = 4 mL

So,

volume of sample = 4 mL

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

the dissolution of polymer can be thermodynamically described in 2 steps.