16. what is the percent composition of a compound that contains 36.03 g of c and 8.06 of h

The percentage composition of the compound is 81.72% of C and 18.28% of H.

Explanation: Percentage composition is the percentage by mass of each element in a compound. It is the ratio of an amount of each element to the total amount of individual elements in a compound, which is then multiplied with 100.

Since the compound above contains only carbon and hydrogen, we will have to find the sum of their masses.

Given 36.03g of Carbon and 8.06g of hydrogen,

36.03g + 8.06g = 44.09g of the compound

%composition= gram of element/gram of compound × 100

%C = 36.03/44.09 × 100

%C= 0.8172 × 100

℅C= 81.72%

Likewise for H

%H= 8.06/44.09 × 100

%H= 0.1828 × 100

%H= 18.28%

Therefore, the compound can be said to contain 81.72% of C and 18.28% of H

idk i’m struggling too

the number of valence electrons for each molecule or ion is shown beneath the structure. remember hydrogen will not have more than two electrons. this hydrogen is part of a covalent bond (sharing two electrons). a double bond here would cause hydrogen to share four electrons with phosphorus.