Calculate the number of moles of o2 produced using the ideal gas law. then, use this value to calculate the number of moles of hydrogen peroxide you began the experiment with. hint: use the balanced equation provided in the lab introduction.

Given data from the lab collated as 291.15k for Temperature, 0.061L for volume and 1atm pressure.

Initial hydrogen peroxide solution is 5ml with a weigh % concentration 6.6%

n=0.0025moles of oxygen AND 0.0097moles of H2O2 were present

Explanation:

2H2O2(aq)2H2O(I)+2O2(g)

Recall the idea gas equation

PV=nRT

n=PV/RT---(1) solving equation (1) using the data in the answer section above.

n=0.0025moles of oxygen is produced.

Recall that for every 100ml of solution you get 6.6g of hydrogen peroxide.

Your 5ml will thus contain

5ml*6.6g H2O2/100ml=0.33g

no of moles if H2O2=0.33/34.015=0.0097moles

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.

2b2t

explanation:

2b2t